> This is true when using compilers as well, right? No, because ... > See Reflec...

		lelanthran 1 day ago \| parent \| context \| favorite \| on: LLMs are not a higher level of abstraction > This is true when using compilers as well, right? No, because ... > See Reflections on Trusting Trust" by Ken Thompson That still results in `f(x) -> y`, not `f(x) -> P(y)`.

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